Prove that root 252 - 5 root 6 + root 294 - 3 root 1/6 = 6 route 7
Added by Nathan F.
Step 1
First, we can simplify the expression by factoring out the common factors under each square root: √252 - 5√6 + √294 - 3√(1/6) = √(36 x 7) - 5√(6) + √(49 x 6) - 3√(1/36) = 6√7 - 5√6 + 7 - (1/2) Show more…
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