Question

Indicate that the root is not a real number. $\sqrt{36}$

   Indicate that the root is not a real number.
$\sqrt{36}$

Precalculus

Robert Blitzer 5th Edition

Chapter 0, Problem 1

Instant Answer

Solved by Expert Natalie Anderson

03/09/2020

Step 1

We can rewrite 36 as six times six. So, we can rewrite the square root of 36 as the square root of six times six. In LaTeX format, this is written as: \[ \sqrt{36} = \sqrt{6 \times 6} \] Show more…

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Indicate that the root is not a real number. $\sqrt{36}$

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Key Concepts

Real Numbers

Real numbers form a continuum that includes all the rational and irrational numbers. They are used to represent quantities along a continuous number line. When working with square roots in the context of real numbers, the radicand must be nonnegative for the output to remain within the real number system.

Complex Numbers

Complex numbers extend the real number system to include expressions involving the imaginary unit 'i', where i² = -1. They are necessary for handling square roots of negative numbers. If the radicand is negative, its square root does not yield a real number but rather a complex one.

Square Root Function

This function returns the nonnegative value that, when squared, yields the radicand. It is defined for nonnegative real numbers, meaning that for any nonnegative input, the square root function produces a unique, real output called the principal square root.

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