Question

Find the linearization to $f(x) = \sec^2 x$ at $a = \frac{\pi}{6}$.

          Find the linearization to $f(x) = \sec^2 x$ at $a = \frac{\pi}{6}$.
        
Find the linearization to f(x) = sec^2 x at a = (π)/(6).

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Find the linearization to f(x) = sec- at a = TT 6
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Transcript

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00:01 For this question, we need to find out the tangent line, which is also called linearization at x equals to pi over 6.
00:11 We're going to use slop point form, that is if we're given a function f of x, and we want to find out a tangent line at x equals to a.
00:21 By the slope point form, we have this formula, y minus f of a, equals to the derivative at a, times x minus a.
00:31 So in this question a is given and we need to figure out what's f of a.
00:36 So f of a is just sine of pi over 6.
00:41 That would be 1 half...
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