$\rightarrow \frac{d}{ds} \left( \frac{s^3 - 4s^2 + 4}{(s-2)(s-1)} \right)_{s=0} = A_1 \rightarrow$
Added by Jennifer D.
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Simplify the left-hand side of the equation: d - 4s^2 + 4 = 4ds(s - 2)(s - 1) Show more…
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