?(r, ?, ?) = \frac{1}{\sqrt{4?} (a_0)^{3/2}} e^{-\frac{r}{a_0}} \\
where a_0 = 0.529 Ã…. We also discussed the physical meaning of \\
$\int_0^r \int_0^{2?} \int_0^{?} |?(r, ?, ?)|^2 r^2 sin?d?d?dr. \\
Now let P(r) = \int_0^r \int_0^{2?} |?(r, ?, ?)|^2 r^2 sin?d?d?, which is the radial probability \\
density. Find r where the radial probability density for the ground state electron is a \\
maximum. Comment on the result you obtained (i.e., explain the physical meaning of \\
the result & comment on the reasonableness). Compare your result with the radius of \\
a Hydrogen atom.