Ace - AI Tutor
Ask Our Educators
Textbooks
My Library
Flashcards
Scribe - AI Notes
Notes & Exams
Download App
robin martinez

robin m.

Divider

Questions asked

BEST MATCH

2. Financial activities of governments involve borrowing funds to build factories. 3. Increased borrowing by consumers and businesses usually results in lower interest rates. 4. A trade deficit involves a country importing more than it exports.

View Answer
divider
BEST MATCH

x P(x) 0 0.1 1 0.2 2 0.3 3 0.4 Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places 0.13 Submit Question

View Answer
divider
BEST MATCH

Which behavior would the nurse expect to observe at night in a patient admitted with sundown syndrome? Agitation Lethargy Depression Mania

View Answer
divider
BEST MATCH

Exercise 2: We consider a particle trapped in an infinite one-dimensional square well represented by the following potential: $\begin{cases} +\infty & x < 0\\ 0 & 0 \le x \le L\\ +\infty & x > L \end{cases}$ 1- Explain why outside the well (in areas $x < 0$ and $x > L$) the particle function is zero ($\Psi_1(x) = \Psi_2(x) = 0$). 2- Find the particle function $\Psi_1(x)$: General solution to Schrodinger's time-dependent equation in Region $0 \le x \le L$. We take $k^2 = \frac{2mE}{\hbar^2}$. 3- By applying the boundary conditions show that $k = \frac{n\pi}{L}$ where $n = 1, 2, 3,..., $ then deduce the particle energy in terms of $n$, $m$, $\hbar$, $L$. Are the particle energy levels connected or discrete (quantized).

View Answer
divider
BEST MATCH

Question 1.(12 marks) 1st April, 2020 an Australian Company purchased inventory from a foreign supplier costing \$FC 50,000 on trade credit. Payment was due on 30th August, 2020. The company's financial year ends on 30th June. The following exchange rates applied: 1st April \$A 1.00 = \$FC 0.8 30th June \$A 1.00 = \$FC 0.6 30th August \$A 1.00 = \$FC 0.9 1. Record all relevant journal entries.

View Answer
divider
BEST MATCH

Moving to another question will save this response. Question 13 Given the following code public class Employee { private String name; private int salary; private Date StartingDate; } Write a parameterized constructor for this class that initializes objects to a given name, a given salary, and a given starting date passed as parameters.

View Answer
divider
BEST MATCH

CREATE TABLE CUSTOMER( CUSTOMER_CODE VARCHAR(5) NOT NULL, /* Unique code of customer */ COMPANY_NAME VARCHAR(40) NOT NULL, /* Company name */ CITY VARCHAR(15) NULL, /* City component of address */ COUNTRY VARCHAR(15) NULL, /* Country component of address */ CONSTRAINT PK_CUSTOMER PRIMARY KEY (CUSTOMER_CODE)); CREATE TABLE PRODUCT( PRODUCT_NAME VARCHAR(40) NOT NULL, /* Product name */ SUPPLIER_NAME VARCHAR(40) NOT NULL, /* Supplier name */ CATEGORY_NAME VARCHAR(30) NOT NULL, /* Product category */ UNIT_PRICE DECIMAL(6,2) NOT NULL, /* Unit price */ CONSTRAINT PK_PRODUCT PRIMARY KEY (PRODUCT_NAME)); CREATE TABLE ORDERS ( ORDER_ID DECIMAL(9) NOT NULL, /* Unique order identifier */ CUSTOMER_CODE VARCHAR(5) NOT NULL, /* Code of customer */ ORDER_DATE DATE NOT NULL, /* Order date */ CONSTRAINT PK_ORDERS PRIMARY KEY (ORDER_ID), CONSTRAINT FK_CUSTOMER_CODE FOREIGN KEY (CUSTOMER_CODE) REFERENCES CUSTOMER (CUSTOMER_CODE)); CREATE TABLE ORDER_DETAIL( ORDER_ID DECIMAL(9) NOT NULL, /* Order identifier */ PRODUCT_NAME VARCHAR(40) NOT NULL, /* Name of ordered product */ QUANTITY DECIMAL(9) NOT NULL, /* Ordered quantity */ DISCOUNT DECIMAL(4,2) NULL, /* Discount applied */ CONSTRAINT PK_ORDER_DETAIL PRIMARY KEY (ORDER_ID, PRODUCT_NAME), CONSTRAINT FK_ORDER_ID FOREIGN KEY (ORDER_ID) REFERENCES ORDERS (ORDER_ID), CONSTRAINT FK_PRODUCT_NAME FOREIGN KEY (PRODUCT_NAME) REFERENCES PRODUCT (PRODUCT_NAME), CONSTRAINT CK_ORDER_DETAIL_QUANTITY CHECK (QUANTITY > 0), CONSTRAINT CK_ORDER_DETAIL_DISCOUNT CHECK (DISCOUNT between 0 and 1));

View Answer
divider
BEST MATCH

Si: 42 * 19 = 32 67 * 28 = 94 Hallar: 95 * 36

View Answer
divider
BEST MATCH

4. a) (-8)+(-7)+(+14)+(+1) c) (+16)+(+12)+(-11)+(-15) 5. a) 5+(-3)+7 d) 18+39+(-71) 6. a) (+4)+(-4) d) 81+(-81) 7. a) (+4)-(+6) e) (+2)-(+1) 8. a) (+45)-(-15) e) (-27)-(+43) b) 2+(-9)+4 b) (-10)+(+7)+(-12)+(+6) e) (-21)+(-29)+50 b) (-7)+(+7) e) (-23)+(+23) c) (-13)+27+(-11) c) (-36)+(+36) f) (-57)+(+57) d) (-6)-(+3) h) 0-(+3) b) (-8)-(+4) f) (-4)-(-2) g) (-8)-(-9) b) (-14)-(+66) f) (-18)-(+42) c) (+68)-(+98) g) (-29)-(-18) d) (+75)-(-15) h) (-99)-(+91)

View Answer
divider
BEST MATCH

13. \sqrt{(\frac{1}{3})^2 - (\frac{1}{5})^2} \times \frac{3}{2} + \frac{2}{5} - (\frac{3}{4}) \times \frac{4}{3} + \frac{3}{4} = x 14. (\frac{1}{\sqrt{2}})^2 - 12 \{ (\frac{2}{3} - \frac{1}{2}) + 6 + \frac{3}{8}(\frac{5}{2} - \frac{2}{3}) - \frac{25}{36} \} =

View Answer
divider