Given: $\angle D \cong \angle F$; GE bisects $\angle DEF$
Prove: $\overline{DG} \cong \overline{FG}$
Proof: Because it is given that $\overline{GE}$ bisects $\angle DEF$, $\angle DEG \cong \angle$ Select Choice by the definition of an angle bisector. It is given that $\angle D \cong \angle F$. By the Select Choice Property, segment Select Choice $\cong$ segment. Select Choice So $\triangle DEG \cong \triangle FEG$ by Select Choice. Therefore $\overline{DG} \cong \overline{FG}$ by CPCTC.
