16.66 points
1 out of 5 attempts
A
With reference to the circuit shown below, think superposition and find that part of $V_1(t)$
due to the current source acting alone. Round your final answers to two decimal places. Leave
any angle $\theta$ as $0^\circ \le \theta \le 360^\circ$.
0.7 $\Omega$
W
$+ v_1 -$
0.7 $\Omega$
0.8 mF
1 mH
-20 cos 2,000 t
-20 sin 2,000 t
$V_1(t) = \text{________} \sin(\text{________}t + \text{________}^\circ)$
