00:01
In the given question, we have been asked, why do you think that the equation for the dependence of temperature and volume for a reversible adiabetic process depends upon whether the gas is monoatomic or polyatomic gas? now we know that for our adiabetic expansion, the q is zero.
00:19
Okay, that means the heat change is zero, which means our internal energy is equal to the work done.
00:26
Now, internal energy is given by ncv d t.
00:30
While the work done is equal to minus p dv.
00:35
And since this is ideal gas, p is equals to n rt over v.
00:40
So we can put the value of p to be equal to nrt over v.
00:45
So this will become minus nrt over v and will get cancelled from both the side.
00:51
And to get a relation between temperature and volume, we need to integrate these value.
00:56
So the limit for temperature is initial to final.
00:59
While the limit for our volume will be v final, v initial to v final...