00:01
So in this question, it says write the lewd structure for each compound with the skeleton structure that is given.
00:07
So the skeleton structure gives us the connectivity between the atoms.
00:12
In the lewd structure, we want to minimize the formal charges.
00:15
We can do this by forming double and triple bonds.
00:18
And also we need to put in the lone pairs of electrons when appropriate.
00:24
So the formula for formal charges number of valance electrons on the atom, which is determined by the group number the atom is in, minus the non -binding electrons on the atom in the compound, minus some of the electrons in bonds divided by two.
00:39
So for a, if we form a triple bond, we're able to minimize the formal charges.
00:49
But the key to determining the fluid structure is that we know that carbon needs to have a valence of four.
00:56
So because of that, carbon needs to have four bonds to it.
01:01
The only way to form four bonds is to triple bond with the neighboring carbon.
01:06
We cannot form a double or triple bond with a hydrogen because hydrogen can only form one bond because it has a valence of one.
01:18
So then for b, we can't form double bonds to hydrogen or chlorine because of the number of valence electrons on hydrogen and chlorine.
01:30
So both of these have a valence of one...