Question
Using the right triangle from Exercise $1,$ show that $\sin ^{2} \alpha+\cos ^{2} \alpha=1$.
Step 1
From the right triangle in Exercise 1, we know that $\sin \alpha = \frac{opposite}{hypotenuse} = \frac{5}{13}$ and $\cos \alpha = \frac{adjacent}{hypotenuse} = \frac{12}{13}$. Show more…
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Key Concepts
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