00:01
We are asked to use a couple of reactions here.
00:05
Let me jot these down.
00:16
This will take me a moment.
00:17
I believe i have three of them.
00:32
And then i have here my heat of reaction, my enthalpy of reaction is negative 906 .2 kj.
01:05
Again, kilojoules.
01:06
And it says, i don't like how it says mole of reaction.
01:12
And finally i have, of course that will yield water.
01:24
And here my heat of reaction is negative 241 .8 kj.
01:35
They all say kilojoules per mole, but i don't like saying kilojoules per mole when i don't have all ones.
01:42
Okay.
01:48
Okay, let's see here.
01:50
Taking a look at my equations.
01:54
Some i may have to reverse, some i may not have to reverse.
01:57
So let's figure out what we're going to do here.
02:00
First of all, let's find something.
02:06
Here's no and here's no.
02:09
So i'm going to keep this equation, same order, and we're going to divide by four.
02:22
And that is my second equation.
02:25
So we're going to divide this by four.
02:28
So let's call this one, two, and three.
02:33
And one, two, and three.
02:36
So i'm going to keep this one in the same order.
02:39
So i'll have nh3, i'm going to leave my states off, plus five over four, o2, yields no plus six over four, h2.
02:57
And my heat of reaction will be negative 906 .2 divided by four.
03:06
Which equals, let me do this.
03:12
906 .2 divided by four is negative 226 .55 kilojoules.
03:23
Very good...