Question
Consider the vector $\mathbf{v}=(-1,3,0,4) .$ Find $\mathbf{u}$ such that(a) $\mathbf{u}$ has the same direction as $\mathbf{v}$ and one-half its length.(b) $\mathbf{u}$ has the direction opposite that of $\mathbf{v}$ and twice its length.
Step 1
The length (or magnitude) of a vector $\mathbf{v}=(-1,3,0,4)$ is given by $\sqrt{(-1)^2+3^2+0^2+4^2}=\sqrt{1+9+0+16}=\sqrt{26}$. Show more…
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