Consider the reaction $$\begin{array}{r}2 \mathrm{H}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \\\Delta H=483.6 \mathrm{kJ} / \mathrm{mol}\end{array}$$
If 2.0 moles of $\mathrm{H}_{2} \mathrm{O}(g)$ are converted to $\mathrm{H}_{2}(g)$ and $\mathrm{O}_{2}(g)$ against a pressure of $1.0 \mathrm{atm}$ at $125^{\circ} \mathrm{C},$ what is $\Delta U$ for this reaction?