00:01
In this problem, we are given a differential equation over here, and we want to decide if this y of x is a solution to this differential equation.
00:13
So to do so, we want to make sure that our y of x is going to be differentiable, which it is.
00:21
I'm going to rewrite y of x equal to x plus 4 to the minus 1, so that it's easier to do.
00:30
Do the chain rule on this.
00:32
And we'll go ahead and go straight to taking the derivative, y prime of x is equal to minus x plus four to the negative two.
00:45
That was just taking the chain rule here and the exponent rule.
00:53
So now that we have y prime of x, we want to plug it into our differential equation up here.
01:01
So we take this whole equation, this negative quantity x plus 4 to the negative and we plug it in here and we add it to y squared where y is 1 over x plus 4 and we check to see that it equals 0.
01:21
So let's do that.
01:23
Y prime is negative.
01:25
You know now i'm going to write it in fraction form again since we're going to be adding and subtracting these fractions...