Question
Use the Laplace transform to solve the given initial-value problem.$y^{\prime}+3 y=2 e^{-t}, \quad y(0)=3$.
Step 1
The Laplace transform of $y^{\prime}$ is $sY(s)-y(0)$ and the Laplace transform of $y$ is $Y(s)$. The Laplace transform of $2e^{-t}$ is $\frac{2}{s+1}$. So, we get \[sY(s)-y(0)+3Y(s)=\frac{2}{s+1}.\] Show more…
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