00:01
Okay, so this problem wants you to evaluate the triple integral of z along the region e, where e is enclosed by the paraboloid z equals x -r -fus y squared, and the plane z equals to 4.
00:15
All right, so the first thing we need to do is convert everything into cylindrical coordinates.
00:20
And i'm looking at the integrand.
00:22
Integrant is just z, and that is going to be the same in rectangular and in cylindrical coordinates.
00:30
We leave that the same.
00:32
Dv, however, that equals to r times dz times dr times d theta.
00:42
And looking at the boundaries, we have the paraboloid z equals xx plus y square, and we know that x squared plus y squared equals to r squared.
00:49
So this can be rewritten as z equals to r squared.
00:53
And the plane is equals four, well, that's just z equals to four in cylindrical coordinates.
00:58
So now we've got everything into cylindrical coordinates.
01:02
Now we have to figure out the boundaries.
01:04
So first we have dz, which is the vertical axis in three dimensions.
01:11
And we know by paraboloid that dz goes from r squared to 4, because the plane of 4 is always going to be the, because z equals r squared is an upper paraboloid facing upwards.
01:30
So the z equals 4 is the ceiling for that paraboloid.
01:35
Next we have dr, and we know that dr is the radius, and we can just figure that out by plugging z equals to 4 into our paraboloid to find when at the top of the maximum radius is...