00:01
To begin this question, we can apply newton's second law in both situations.
00:05
So, for the first situation, newton's second law tells us that the net force is equal to the object's mass times the acceleration.
00:15
But the object's net force, in this case, is equal to f a plus fb.
00:22
He knows that i'm adopting that everyone pointing towards the right is positive and everyone pointing towards the left is negative.
00:30
So here we have f .a plus fb, and this is equal to the mass times the acceleration.
00:39
On the second situation, the net force, let me do this.
00:44
In the second situation, the net force is equal again to the mass times the acceleration.
00:50
But now the acceleration is different, so let me call it a prime.
00:54
And the net force is given by f a minus fb, because now the force b is point.
01:02
To the left.
01:04
And this is equal to the mass times the new acceleration.
01:08
So this is what you get by using newton's second law.
01:12
Now what can we do to solve for f .a and fb? well, note that this is a system of equations.
01:19
In the first situation, we have f .a plus fb equals to 8 times 0 .5, and this is equals to 4.
01:32
Therefore, in the first situation, we have f .a plus fb is equal to 4.
01:40
In the second situation, we have f .a.
01:45
Minus fb is equal to 0 .4 times 8, which is equal to 3 .2...