Question
Solve Problems $45-52$ using Cramer's rule:$$\begin{array}{rr}x+y & =-4 \\2 y+z & =0 \\-x+z & =5\end{array}$$
Step 1
The coefficient matrix $A$ is given by $$ A = \begin{bmatrix} 1 & 1 & 0 \\ 0 & 2 & 1 \\ -1 & 0 & 1 \\ \end{bmatrix} $$ and the constant vector $\mathbf{b}$ is given by $$ \mathbf{b} = \begin{bmatrix} -4 \\ 0 \\ 5 \\ \end{bmatrix} $$ Show more…
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