00:01
In this problem, we're being asked to take the equation v equals 1 3rd bh and solve for h.
00:07
In other words, we're trying to isolate h all by itself on one side of the equation, meaning we have to move whatever's on the side with the h to the other side.
00:16
Well, the first thing i notice if you have a fraction, which can sometimes be confusing.
00:21
So what i'm going to do first is i'm going to multiply both sides of my equation by 3.
00:26
And the reason why i'm going to multiply by 3 is because if i'm going to multiply by 3, multiply 3 times 1 third, i would get 3 thirds, which is really just equal to 1.
00:35
So essentially, those 3s will cancel each other out.
00:39
So on the left -hand side of the equation, we have 3 -v, which is 3 -v, and on the right -hand side, we are simply left with b times h.
00:48
Well, remember, our goal is still to get h by itself.
00:52
Well, what's happening to h? well, it's getting multiplied by b.
00:56
So to move the b to the other side of the equation, we have to do the opposite...