Question
Solve each system using matrices. If there is no solution or if there are infinitely many solutions and a system’s equations are dependent, so state.$\left\{\begin{aligned} x-3 y+z &=2 \\ 4 x-12 y+4 z &=8 \\-2 x+6 y-2 z &=-4 \end{aligned}\right.$
Step 1
Step 1: First, we write the system of equations in augmented matrix form: \[ \begin{bmatrix} 1 & -3 & 1 & 2 \\ 4 & -12 & 4 & 8 \\ -2 & 6 & -2 & -4 \end{bmatrix} \] Show more…
Show all steps
Your feedback will help us improve your experience
Ankit Gupta and 68 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve each system using matrices. If there is no solution or if there are infinitely many solutions and a system’s equations are dependent, so state. $\left\{\begin{aligned} 3 x-y+2 z &=4 \\-6 x+2 y-4 z &=1 \\ 5 x-3 y+8 z &=0 \end{aligned}\right.$
Systems of Linear Equations
Matrix Solutions to Linear Systems
Solve each system using matrices. If there is no solution or if there are infinitely many solutions and a system’s equations are dependent, so state. $\left\{\begin{aligned} x-2 y-z &=2 \\ 2 x-y+z &=4 \\-x+y-2 z &=-4 \end{aligned}\right.$
Use matrices to solve each system of equations. If the equations of a system are dependent or if a system is inconsistent, state this. $\left\{\begin{array}{l}2 x+3 y-z=-8 \\ x-y-z=-2 \\ -4 x+3 y+z=6\end{array}\right.$
More on Systems of Equations
Solving Systems of Equations Using Matrices
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD