00:01
All right guys, so today we'll be working with systems of nonlinear equations with these two logarithmic equations.
00:08
So the one thing to remember about logarithmic equations like these ones is the standard rule where when we say log base a of b equals c, let's say.
00:20
And that could be rewritten as a raised to the power of c equals b.
00:27
So, we can use those logarithmic rules and move forward with these two equations, saying that here, y equals x cubed, and then here, x to the fifth equals 4y.
00:51
Then let me just rewrite these again, so it's easier to see.
00:54
So y equals x cubed, and 4y equals x to 5th.
01:01
We can just use substitution method and plug it into, plug this y into this y.
01:08
So then we can say 4 times x cubed equals x to the fifth.
01:17
That would mean that 4x cubed equals x to the fifth.
01:24
We can divide x cubed on both sides and get x 5 minus 3.
01:35
Rules 5 minus 3 so x squared so 4 equals x squared because these x cubes cancel out and then we have this 5 minus this 3 right here so we have 4 equals x cubed which means that we take the square root of both sides and we get x equals plus or minus 2 because positive 2 could result in 4 1 squared and negative 2 could result in 4 1 squared as well...