00:01
We're being asked to solve the given radical equation.
00:03
Well, because both radicals are isolated, to get rid of them, what we need to do is square both sides of our equation.
00:11
So on the left -hand side, when we square the radical, remember, it cancels out the radical and we're just left with what's inside, which in this case is 3x plus 1.
00:21
Now, on the right -hand side, again, when we square that radical, it's going to cancel out the radical, and we're just left with what's inside, which is 5x minus 8.
00:31
And now we just need to solve this equation.
00:33
Well, to do this, i'm going to subtract 3x from both sides, because the 3x will cancel, so i get 1 equals, well, 5x minus 3x is 2x, so i have 2x minus 8.
00:48
And now we have a 2 step.
00:50
So i'm going to add 8 to both sides of the equation, and 1 plus 8 is equal to 9.
00:55
So i have 9 equals to 2x because the 8s cancel, and then i'm going to divide by 2, and 9 divided by 2 is 4 .5.
01:03
So what i've found is x is equal to 4 .5.
01:07
However, i have to go back and check to make sure that it makes the equation true.
01:13
Well, to check, we need to substitute 4 .5 back in for x...