00:01
We're being asked to solve the equation and determine if it's a conditional equation and this inconsistent equation or an identity.
00:07
So let's go ahead and solve.
00:08
Well, to do that, we have to get rid of our parentheses.
00:10
So let's distribute.
00:11
Well, 2 times 1 half x is just positive 1x, and 2 times 3 over 2 is positive 3.
00:19
Then i'll bring down the minus 7 over 2.
00:21
Now we have to distribute by 3 halves.
00:23
Well, 3 halves times x is 3 halves x, and 3 over 2 times 1 is just positive 3 over 2.
00:31
Now, in front of the next set of prephases, we have a negative sign, which remember means we have to change the signs of both of these terms.
00:39
So the positive 1 .5x will become negative 1 .5x, and the positive 2 will become negative 2.
00:47
Now, i see we have fractions, so to get rid of them, i'm going to multiply the whole equation, both sides by our common denominator, which in this case is 2.
00:56
So let's distribute this.
00:59
Well, 2 times 1x is 2x, 2 times 3 is positive 6, and 2 times negative 7 over 2, it's just negative 7...