Network-based intrusion detection host based intrusion detection. a. is less expensive than b.

Network-based intrusion detection host based intrusion...

Key Concepts

Cost Considerations in IDS Deployment

Cost considerations in IDS deployment include factors such as hardware and software expenses, scalability, integration complexity, and ongoing maintenance. Generally, network-based IDS tends to be more expensive than host-based IDS due to the need for additional resources and infrastructure to monitor network traffic comprehensively.

Host-based Intrusion Detection (HIDS)

HIDS monitors individual devices or hosts, focusing on internal system activity such as file modifications, process behaviors, and log entries. It is generally less expensive to deploy than NIDS because it leverages existing host resources and does not require extensive network infrastructure investments.

Intrusion Detection Systems (IDS)

IDS are systems designed to monitor computer networks or systems for malicious activity or policy violations and respond to detected intrusions. They are a critical component of cybersecurity frameworks, used to detect, alert, and sometimes respond to potential security breaches.

Network-based Intrusion Detection (NIDS)

NIDS analyzes traffic on an entire network segment, examining network packets in real time and identifying anomalies that may indicate a security threat. This type of IDS typically requires dedicated hardware and extensive deployment across network points, resulting in higher costs due to its complexity, scalability requirements, and maintenance.

Transcript

00:01 For this problem, we are told to consider a double ids with system a and system b.

00:05 We're told that if there is an intruder, system a sounds an alarm with probability 0 .9.

00:11 And system b sounds an alarm with probability 0 .95.

00:14 We then told that if there is no intruder, the probability that system a sounds an alarm, i .e.

00:19 A false alarm, is 0 .2.

00:20 And the probability that system b sounds an alarm is 0 .1.

00:24 In part a, we are asked to use symbols to express the four probabilities given.

00:29 So what i'll do is write that the probability of alarm a going off, that's event, i'll call that event a, given that there is an intruder, so p of a given i is equal to 0 .9, and then we have p of b given i equals 0 .95.

00:50 Then we'd have for the false positives, p of a given i complement, so no intruder equals 0 .2, and p of a given, or p of b given i, c, one moment here, p of b given i complement, equals 0 .1.

01:10 Then for part b, we are asked, if there is an intruder, what is the probability that both systems sound an alarm? so this would be the probability of essentially a and b given i.

01:28 Now, we can find this by evaluating the probability of a given i plus the probability of b given i minus the product of those probabilities.

01:42 That would be the product or the probability of their intersection given that, or essentially given that there is an intruder, and we are making the assumption that the two alarms going off would be independent...

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