Question

Given any language $L$ that does not include $\Lambda$, let us define its cousin language $|L|$ as follows: For any string of $a$ 's and $b$ 's, if the word formed by concatenating the second, fourth, sixth, . . . letters of this string is a word in $L$, then the whole string is a word in $|L|$. For instance, if $b b b$ is a word in $L$, then $a b a b b b b$ and $b b a b a b a$ are both words in $|L|$. (i) Show that if there is some PDA that accepts $L$, then there is some PDA that accepts $|L|$. (ii) If $L$ is regular, is $|L|$ necessarily regular too?

   Given any language $L$ that does not include $\Lambda$, let us define its cousin language $|L|$ as follows: For any string of $a$ 's and $b$ 's, if the word formed by concatenating the second, fourth, sixth, . . . letters of this string is a word in $L$, then the whole string is a word in $|L|$. For instance, if $b b b$ is a word in $L$, then $a b a b b b b$ and $b b a b a b a$ are both words in $|L|$.
(i) Show that if there is some PDA that accepts $L$, then there is some PDA that accepts $|L|$.
(ii) If $L$ is regular, is $|L|$ necessarily regular too?
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Introduction to computer theory
Introduction to computer theory
Daniel I. A. Cohen 2nd Edition
Chapter 14, Problem 19 ↓

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Step 1

Let $M$ be a PDA that accepts $L$. We can modify $M$ to accept $|L|$ by adding an extra state and transitions. First, we add a new start state $q_0'$ and an epsilon transition from $q_0'$ to the original start state $q_0$ of $M$. This allows us to start in  Show more…

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Given any language $L$ that does not include $\Lambda$, let us define its cousin language $|L|$ as follows: For any string of $a$ 's and $b$ 's, if the word formed by concatenating the second, fourth, sixth, . . . letters of this string is a word in $L$, then the whole string is a word in $|L|$. For instance, if $b b b$ is a word in $L$, then $a b a b b b b$ and $b b a b a b a$ are both words in $|L|$. (i) Show that if there is some PDA that accepts $L$, then there is some PDA that accepts $|L|$. (ii) If $L$ is regular, is $|L|$ necessarily regular too?
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