00:01
Hello, we're looking at chapter 5, section 1, problem number 34, given the function f of x equals x times 2 to the negative x squared, you want to find the critical numbers and the open intervals where the function f of x is increasing and or decreasing.
00:22
So we're going to start by finding the derivative of f because critical number.
00:31
Numbers occur when the first derivative is equal to zero or undefined.
00:36
So to do so i'm going to remember that d dx of 2 to the u is equal to 2 to the u times the natural log of our base, so natural log of 2, and then of course times u prime for chain rule.
01:00
So looking at my f of x, i see it as a product rule first and foremost, which means i'm going to go first times the derivative of the second plus the second times the derivative of the second.
01:13
So first x times the derivative of the second.
01:18
So derivative of 2 to the u again is 2 to the u, which is negative x squared, times natural log of the base, so natural log of 2 times the derivative of u, so derivative of negative x squared is negative to x.
01:39
So so far i have the first times the derivative of the second, and then plus the second, so 2 to the negative x squared, times the derivative of the first, derivative of x is, of course, 1.
01:56
So i want to clean this up a bit, recognizing i can factor out base 2 to the negative x squared from both terms.
02:07
And so when i do, i will be left with x times negative 2x, so negative 2x squared times the natural log of 2 to give me the first term.
02:19
And the second is just a plus 1.
02:24
So i can write that as 1 minus 2x squared natural log of 2, all over 2 to the positive x squared.
02:40
So i know to find for part a, to find my critical numbers, i need to set the derivative.
02:48
So f prime of x equal to zero or undefined.
02:51
It's not going to be undefined because when i set the denominator equal to zero, 2 to the x squared is always positive.
02:59
So another 0.
03:00
So i'm not going to get anything from that.
03:02
So then i'm just going to find my critical numbers by setting 1 minus 2x squared natural log of 2.
03:10
Equal to zero.
03:12
And so i'm going to wind up with, let's see, i'll move this over and then divide.
03:19
So i can write that as 1 equal to 2 x squared natural log of 2.
03:29
So x squared is going to equal.
03:33
If i move this, divide by 2 and natural log of 2.
03:40
And so when i take the square root, i'm going to get x equals so negative the square root of 1 over 2 natural log of 2 or x equals the positive square root of 1 over 2 natural log of 2...