00:01
All right we would like to find v0 in this network here.
00:04
Let's see what we can figure out.
00:06
What i'm noticing here is that immediately through this current we see through this the line of wire we have vx divided by one is just current of vx amps.
00:22
Of course there's vx amps going through here as well which means that the voltage differential here must be 2 vx volts because of the 2 amp thing which means that this guy is going to be 3 vx volts relative to up here.
00:40
We're defining down here to be ground so this is actually zero and that means that up here is negative 3 vx is equal to v0.
00:50
That's not super useful to us yet because of course we need to find out what vx is but it means once we find out what vx is we can multiply by negative 3 and we get v0.
01:02
Now let's see what else we got.
01:04
I am noticing here we've got a downward current of vy divided by 2 amps and likewise here this is vy divided by 2 which means that down here is zero up here is twice vy divided by 2 is just vy that's also equal to v0.
01:30
So vy is v0 is equal to negative 3 times vx.
01:36
That's lovely, that's nice...