00:01
All right, so this problem here asks us to find a quadratic equation here in the form of y equals a x squared plus c using these given points.
00:10
And so this time we don't have a vertex point, so that does not give us c.
00:15
So when we have this many unknowns in an equation, and we will know an x and a y, you can see that we have an a and a c left.
00:24
We just need two equations for that.
00:27
So we'll just plug in each of the one points and then solve for that.
00:32
We can use either substitution or elimination.
00:35
And so what we have here, i'll start with the bigger numbers here because i'm going to use elimination.
00:44
And so if i plug in 89 for y, and that's equal to a and x squared is negative 3 squared plus c and then i'll use this other point.
00:57
So i have 39 is equal to a times two squared plus c.
01:04
And so i chose elimination because if i just subtract each one of these terms from these bottom terms from the top term, then that gets rid of the c.
01:14
So that's just kind of a quick and easy way to do that.
01:18
And so here 89 minus 39 is 50...