00:01
In this problem, we are evaluating this limit, the limit of the square root of x plus 6 as x approaches 3.
00:13
So as x approaches 3 of the square root of x plus 6, we can do this problem in several ways.
00:23
First, we can use the fact that the limit of a square root function is the square root of its limit.
00:30
So the square root of the limit of x plus 6 as x approaches 3.
00:41
And what is the limit of x plus 6 as x approaches 3? well, if you've done the previous problems, you can see that x plus 6 is a polynomial.
01:00
So since it's a polynomial, you can use the fact that the limit of a polynomial as c is just the value.
01:11
The y value when you plug in c so if you plug in three into x plus six then we have the nine so therefore this limit is equal to nine so therefore we have the square root of nine which is equal to three so therefore the limit of the square root of x plus six as x approaches three is square root of nine which is three another easier way, much simpler way, but it uses the same concepts behind it is just to plug in three directly, which is what we did...