00:03
All right, so let's look at the first two vectors.
00:17
We have 1 ,000, 0 ,000, negative 1, 0 ,0, 1, c sub 1, c sub 2, equal to 0 ,000, 0 ,000.
00:34
So we can say c sub 1 plus c sub 2 equals 0, negative c sub 1 equals 0.
00:50
So that means that c sub 1 equals 0, negative c sub 2 equals 0.
01:04
So we can say c sub 2 equals 0.
01:09
So we can say that v sub 1 and v2 are independent.
01:18
Now, with v3, we have 1 -1 -1 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -6 -1, c -7 2, c -7 -3 equal to 0 -0.
01:52
Now we can read this as c -1 plus c -2 plus c -7 -3 equals 0, negative c -1, equals 0, so c sub 1 equals 0, negative c sub 2 equals 0, so c sub 2 equals 0, and c sub 3 follows 2 equals 0.
02:21
So v sub 1, v2, 3, 3 are independent.
02:42
Now with v4, we have the matrix 1 ,1, 1 ,0, negative 1 0 ,000, negative 1 0 ,000 ,000, 0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 c -s7 -1, c -7 2, c -7 -3, c -7 4.
03:11
This is going to equal 0 -0 -0, 0 -0, giving us c -1 plus c -s2 plus c -7 -3 equals 0, or c -1 equals...
03:28
Actually, let's just keep like that for now...