Question
Find the differential of the function.$$u=\sqrt{x^{2}+3 y^{2}}$$
Step 1
The partial derivative of the function with respect to x is given by: $$ \frac{\partial u}{\partial x}=\frac{1}{2}(x^{2}+3y^{2})^{-\frac{1}{2}}(2x)=\frac{x}{\sqrt{x^{2}+3y^{2}}} $$ Show more…
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Find the differential of the function. $ u = \sqrt{x^2 + 3y^2} $
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