00:01
This problem is a parallel circuit with a few current supplies and a couple of branches with resistors.
00:10
And to work this, i am going to use the understanding that the voltage drop across each branch is equal.
00:18
And i don't know what that is.
00:20
So i'm just going to assign it variable v .s.
00:23
And that way i can use that to figure out what some of these currents are.
00:28
The other thing i'm going to use is kirchhoff's current law.
00:33
The sum of the currents at any node is equal to zero.
00:37
And i'm going to pick the top left -hand node.
00:40
So going into that, i can see that i have 6 milla -amps.
00:47
So i'll draw that over 1 ,000.
00:50
And then i also, coming out of it, i have v -sub -s, and that's over 1 kilo -oam.
01:03
And then the next one coming into the node from that next voltage or current supply.
01:09
So i draw it minus.
01:11
I have v -x.
01:13
That's over 1 ,000.
01:15
Then the next branch coming out, i have v -sub -s.
01:21
Again, the voltage across that branch, and that's over 2 kilo -ooms...