Question
Evaluate the integral.$\int \tan ^{2} x \sec x d x$
Step 1
This gives us: \[\int \tan ^{2} x \sec x d x = \int (\sec^2x - 1) \sec x d x = \int \sec^3x dx - \int \sec x dx\] We will denote these two integrals as $I_1$ and $I_2$ respectively. Show more…
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