Question
Evaluate the definite integral.$$\int_{0}^{1} \sqrt{2 x}(\sqrt{x}+\sqrt{2}) d x$$
Step 1
We distribute the $\sqrt{2x}$ to both terms in the parentheses to get: $$\int_{0}^{1} \sqrt{2 x}(\sqrt{x}+\sqrt{2}) d x = \int_{0}^{1} (2x\sqrt{x} + 2\sqrt{2x}) dx$$ Show more…
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