Question
Evaluate each improper integral whenever it is convergent.$$\int_{-\infty}^{\infty} x e^{1-x^{2}} d x$$
Step 1
We can choose $c=0$ for convenience. This gives us: $$\int_{-\infty}^{\infty} x e^{1-x^{2}} dx = \int_{-\infty}^{0} x e^{1-x^{2}} dx + \int_{0}^{\infty} x e^{1-x^{2}} dx$$ Let's call the first integral $I_1$ and the second integral $I_2$. Show more…
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