00:01
All right, so for a, we compute a to the 20th, and then we do our conjecture and say that the limit as t approaches infinity of a to the t, or that would be equal to a to the 20th, which is going to be the matrix, 0 .36, 0 .36, 0 .36, and then 0 .26, 0 .26, 0 .26, 0 .26, 0 .26, 0 .28 .38.
00:32
In the bottom 0 .38, 0 .38.
00:40
And then for the eigenvalues, for b, we'd say, for part b, we do lambda sub 1 equals 1, and then a lambda 2 3 is going to be equal to 1 plus or minus i times the square root of 39 over 20.
01:06
And then they are all distinct.
01:09
Say that a is going to be diequalizable over the complex numbers over c.
01:20
And then for the equilibrium distribution, for c, we solve ax is equal to x.
01:30
And get that the eigenvalue for lambda equals 1 is proportional to the matrix 18, 13, 19.
01:39
And then we normalize so the entries add up to 1...