00:01
Well, given date, r is equal to a times sine omega t, sine omega t, plus a times cosine of omega t.
00:28
And this one is in the j -cap direction.
00:37
Now, let's find the magnitude of distance from the origin.
00:42
So the magnitude r is equal to square root of rx whole square plus ry whole square.
00:57
Now we have r x and r y, x and y components of r so far.
01:03
So this is equal to square root of a sine omega t, a sine omega t whole square plus a a, a square, cosine square omega -t, and this equals a -into, square -square -o -tquare -o -t, and hence it's equal to a, right, since this factor is equal to 1, right, since this factor is equal to 1.
02:01
Which is equal to a, the amplitude.
02:05
So at any instant of time, the object is at a constant distance from origin equal to a.
02:14
So the distance is always constant, and that is equal to a.
02:22
Now, this path is only possible when the path is circular, and the radius of circular path is always a constant.
02:39
So it is the same from the center.
02:44
Now, so this was part a, right? now let's do part b...