Question
(a) RCHO(b) $\mathrm{RCH}_{2} \mathrm{OH}$(c) $\mathrm{RCOOH}$(d) $\mathrm{R}-\mathrm{C} \equiv \mathrm{CH}$
Step 1
The reaction with sodium will replace the acidic hydrogen, and the C- will attack the oxygen. This will result in the formation of $\mathrm{OH}^{-}$ and $\mathrm{RCH}_{2}\mathrm{ONa}^{+}$. However, this is not the correct product. Show more…
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