00:01
So we have r of x is equal to x over x minus two.
00:06
And we're looking at the characteristic of the vertical and horizontal asymptotes by doing some little bit of research.
00:12
So here's your table one.
00:14
And you have when x is 1 .5, 1 .9, 1 .99, 1 .999.
00:22
And we want to find what happens when we have that function.
00:27
And so one nice thing you can do is you can store into your calculator and you can type in like 1 .5 and then the stow button as x.
00:41
I'm going to do that right now, 1 .5 stow as x.
00:44
And then just hit enter.
00:46
And then you can type in to evaluate these expressions.
00:50
You can take x divided by left parentheses x minus two and just type it in.
00:57
And then i find out that this value for r of x is equal to negative 3.
01:02
When i go back, i can change my input as 1 .9 store as x.
01:09
And then i can just go back up and have that evaluate that expression.
01:13
Again, i get negative 19.
01:15
When i plug in 1 .99 for x and i do 1 .99 and either just plug it in here and figure out the value, or again, you can do the store and and then just go back up to your calculator and have it recalculate that expression, i get negative 199.
01:35
When i plug 1 .9999 in store that as x and then evaluate this expression, i end up getting negative 1 ,9999.
01:50
So i can see that as i get closer and closer to a value of 2, i'm going to negative infinity.
01:57
And then when we look at table 2, and we plug in some values that are to the right of 2, and plug in 2 .5, 2 .1, 2 .01, 2 .001.
02:12
Again, i can do exactly the same thing.
02:14
Take 2 .5 and store it as x.
02:16
And then i can go back on my calculator and have it do that calculation.
02:20
I get 5.
02:24
When i get closer, and i have 2 .1 stored as x and plug it in, i find out that that expression becomes 21.
02:34
And i'm not going to continue to go further and plug these other values in...