Question
$4-30$ Evaluate the integral.$$\int_{0}^{1} x \sqrt{x^{2}+4} d x$$
Step 1
Let $u = x^2 + 4$. This transforms our limits of integration. When $x = 0$, $u = 0^2 + 4 = 4$. When $x = 1$, $u = 1^2 + 4 = 5$. So our new limits of integration are from 4 to 5. Show more…
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