00:01
For this problem, we are asked to find a parametric representation for the plane through the origin that contains the vectors i -hat minus j -hat and j -hat minus k -hat.
00:10
So to begin, we can use the sort of standard form for the equation of a plane when we are given a point that it passes through as well as two vectors, which would be r of uv.
00:24
It's going to equal x -not.
00:26
That's the x -cordinate of our point plus a1 plus b1.
00:32
Or i should be more careful here, u -a -1 plus v -b -1, i -hat, then similar process for the j -hat and k -hat.
00:47
The point of saying this is that essentially we can just read off what each of these components are going to be from the vectors that are given to us, as well as from the fact that we were told it passes through the origin.
01:00
Because it passes through the origin, that means that we know that the x -not, y, and z -not will just be zeros...