In deriving the expression for the flexural stress under pure bending, $\sigma_x=\frac{M y}{1}$, the stress $\sigma_y$ is assumed to be negligible; i.e., $\left|\sigma_y\right| \ll\left|\sigma_x\right|$. Consider now, for example, a beam of rectangular cross-section, $b \times 2 c$, subjected to lateral loads $q(x)$, as shown in Fig. (8P.94a). Clearly since the stress $\sigma_y=q / b$ at the top of the bearn and $\sigma_y=0$ at the bottom, $\sigma_y=f(y)$, i.e $\sigma_y$ varies with $y$ and is not zero throughout the beam. Note that here positive $\sigma_y$ is compressive.
We first isolate an element ( $b \times 2 c \times d x$ ) [see Fig. (8P.94b)]; shear forces $V$ and $V+\Delta V$ act on the two faces as shown. Let us now isolate a portion of the element, $b \times(1-\alpha) c \times d x$, where $y=-\alpha c(0 \leq \alpha \leq 1)$, as shown in Fig. (8P.94c). Since $q(x) \neq 0$, $V=V(x)$ on any cross-section; therefore, acting on this portion of the element there exist, in addition to $q(x)$, (i) shear forces (which are due to the shear stresses $\mathrm{r}_{x y}$ ) on the left and right faces, which we denote as $\Delta V$ and $\mathrm{d}(\Delta V)$, respectively, and (ii) a stress $\sigma_y$. (Note that here ' $\Delta$ ' refers to the portion of the cross-section and ' $d$ ' refers to the difference of the left and right faces.)
(a) From equilibrium considerations, show that
$$
\sigma_y=\frac{1}{b}\left[q(x)+\frac{d(\Delta V)}{d x}\right]
$$
and hence, using the relation $\mathrm{dV}(x) / \mathrm{d} x=-q(x)$,
$$
\sigma_y=\frac{q(x)}{b}\left[1-\frac{1}{l} \int_{-c}^{-a x} Q(y) d y\right] \text {, }
$$
where $Q(y)$ is the first moment about the centroidal z-axis of the portion of the cross-section $b \times(1-\alpha) c$.
(b) By evaluating the integral, obtain an expression for $\sigma_y$, namely
$$
\sigma_y(x, \alpha)=\frac{q(x)}{4 b}\left[2+3 \alpha-\alpha^3\right]
$$
or
$$
\sigma_y(x, y)=\frac{q(x)}{4 b}\left[2-3 \frac{y}{c}+\frac{y^3}{c^3}\right] .
$$
(c) Plot $\sigma_y$ as a function of $y$ in the beam. What is $\sigma_y$ at the neutral axis? of a simply supported beam subjected to a uniformly distributed load $q_0$ and therefore $R_\sigma \ll 1$ if $d / L \ll 1$.