Show that when the mapping from $\boldsymbol{\theta}_0$ to $\boldsymbol{\pi}_0$ is linear, $\boldsymbol{\pi}_0=\mathbf{H} \boldsymbol{\theta}_0$ for a known $S \times P$ matrix $\mathbf{H}$ with $\operatorname{rank}(\mathbf{H})=P$, the CMD estimator $\hat{\boldsymbol{\theta}}$ is
$$
\hat{\boldsymbol{\theta}}=\left(\mathbf{H}^{\prime} \hat{\boldsymbol{\Xi}}^{-1} \mathbf{H}\right)^{-1} \mathbf{H}^{\prime} \hat{\boldsymbol{\Xi}}^{-1} \hat{\boldsymbol{\pi}}
$$
Equation (14.89) looks like a generalized least squares (GLS) estimator of $\hat{\boldsymbol{\pi}}$ on $\mathbf{H}$ using variance matrix $\overline{\boldsymbol{E}}$, and this apparent similarity has prompted some to call the minimum chi-square estimator a "generalized least squares" (GLS) estimator. Unfortunately, the association between CMD and GLS is misleading because $\hat{\pi}$ and $\mathbf{H}$ are not data vectors whose row dimension, $S$, grows with $N$. The asymptotic properties of the minimum chi-square estimator do not follow from those of GLS.