C = (x+3)/(√(x)-2) ÷((√(x)-1)/(√(x)+2) - (5√(x)-2)/(x-4))

Name: C = (x+3)/(√(x)-2) ÷((√(x)-1)/(√(x)+2) - (5√(x)-2)/(x-4))
Uploaded: 2023-07-22T03:19:20-08:00
Duration: 21 s
Channel: Numerade
Description: C = (x+3)/(√(x)-2) ÷((√(x)-1)/(√(x)+2) - (5√(x)-2)/(x-4))

Question

Vivek Kumar · Answer

Let us square this on both sides to under root x whole square is equal to under root 3x plus 4 w

Khushbu Rani · Answer

all right there is a question in this i had to solve 2x minus 1 plus under root x equal to 2 oka

Aman Gupta · Answer

In this problem, we need to note that the square roots have to be defined, which means that x mi

Aman Gupta · Answer

In this problem, the equation can be rewritten as x plus 1 power 1 by 3 plus x plus 2 power 1 by

Ankit Gupta · Answer

Now isolate O1 radical term right hand side and you&#x27;ll find x plus 2 equal to 2 minus under root

Question

C = \frac{x+3}{\sqrt{x}-2} \div \left(\frac{\sqrt{x}-1}{\sqrt{x}+2} - \frac{5\sqrt{x}-2}{x-4}\right)

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