\lim_{x \to -1} \frac{x^3 + 4x^2 + 4x + 1}{x + 1} =
Added by Jim M.
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This means that x is getting closer and closer to -1, but never actually reaches -1. To do this, we can simply substitute -1 for x in the expression: (-1)3 + 4(-1)2 + 4(-1) + 1 = -1 + 4 - 4 + 1 = 0 So the expression evaluates to 0 when x approaches -1 from the Show more…
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