\begin{cases} x^2 + y^2 + xy = 3 \\ x + y = 1 \end{cases}
Added by Jeremy H.
Close
Step 1
We can solve for x by subtracting y from both sides of the equation: x = 1 - y Now, substitute this expression for x into the first equation: (1 - y)^2 + y + (1 - y)y = 3 Expand the squared term: (1 - 2y + y^2) + y + (1 - y)y = 3 Combine like terms: 1 - 2y Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 68 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
. $(x+2 y+3)+i(3 x-y-1)=0$
COMPLEX NUMBERS
Complex algebra
$$ \begin{aligned} &\frac{x}{3}+\frac{y}{2}=0 \\ &\frac{x}{2}+y=-1 \end{aligned} $$
Matrix Algebra and Applications
Matrix Inversion
Find $x+y, x-y, x y,$ and $x / y$. $$x=-3+i ; y=i+\frac{1}{2}$$
More About Functions and Equations
Complex Numbers and Quadratic Equations
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Watch the video solution with this free unlock.
EMAIL
PASSWORD