Question

$\lim_{x \to \infty} (x^2 + 1)\sin\left(\frac{x+1}{x^2+1}\right)$ A-) $\frac{1}{2}$ B-) 2 C-) $\infty$ D-) 0 E-) 1

          $\lim_{x \to \infty} (x^2 + 1)\sin\left(\frac{x+1}{x^2+1}\right)$ 
A-) $\frac{1}{2}$
B-) 2
C-) $\infty$
D-) 0
E-) 1

limx →∞ (x^2 + 1)sin((x+1)/(x^2+1))
A-) (1)/(2)
B-) 2
C-) ∞
D-) 0
E-) 1

Added by Soledad L.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Sutara K

Step 1

First, we need to simplify the expression inside the sine function. Using the identity sin(A + B) = sinAcosB + cosAsinB, we can rewrite sin(x+1) as sin(x)cos(1) + cos(x)sin(1). Show more…

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X + 1 Iu x + 1) sinf AoC x + 1

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Question

$\lim_{x \to \infty} (x^2 + 1)\sin\left(\frac{x+1}{x^2+1}\right)$ A-) $\frac{1}{2}$ B-) 2 C-) $\infty$ D-) 0 E-) 1

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