What is the local maximum point of $y = x^4 - 2x^2 + 2$
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To do this, we take the partial derivatives with respect to x and z and set them equal to zero: ∂H/∂x = 2z = 0 ∂H/∂z = 2x = 0 This gives us the critical point (x,z) = (0,0). Show more…
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