(1 point) Find the distance from the point (3, 1, 5) to the plane $-5x - 2y + 1z = 0$.
Added by Jessica P.
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Step 1
First, we need to find the equation of the plane. The given equation is 4x + y = -1. We can rewrite it as y = -4x - 1. So, the normal vector to the plane is (4, 1, 0). Show more…
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